DR ANTHONY MELVIN CRASTO,WorldDrugTracker, helping millions, A 90 % paralysed man in action for you, I am suffering from transverse mylitis and bound to a wheel chair, With death on the horizon, nothing will not stop me except God................DR ANTHONY MELVIN CRASTO Ph.D ( ICT, Mumbai) , INDIA 25Yrs Exp. in the feld of Organic Chemistry,Working for GLENMARK GENERICS at Navi Mumbai, INDIA. Serving chemists around the world. Helping them with websites on Chemistry.Million hits on google, world acclamation from industry, academia, drug authorities for websites, blogs and educational contribution

Wednesday 19 November 2014

TAK 733



TAK-733
CAS: 1035555-63-5
Synonym: TAK-733; TAK 733; TAK733.
IUPAC/Chemical name: 
(R)-3-(2,3-Dihydroxypropyl)-6-fluoro-5-(2-fluoro-4-iodophenylamino)-8-methylpyrido[2,3-d]pyrimidine-4,7(3H,8H)-dione
Chemical Formula: C17H15F2IN4O4
Exact Mass: 504.01060
Molecular Weight: 504.23
Elemental Analysis: C, 40.49; H, 3.00; F, 7.54; I, 25.17; N, 11.11; O, 12.69
Phase I clinical studies for cancer treatment.Takeda Pharmaceutical
Solid Tumors Therapy



Figure US08436200-20130507-C00012

The synthetic process of the present invention allows for the preparation of (R)-3-(2,3-dihydroxypropyl)-6-fluoro-5-(2-fluoro-4-iodophenylamino)-8-methylpyrido[2,3-d]pyrimidine-4,7(3H,8H)-dione while avoiding the use of a fluorinating reagent in the last step. That is, the present invention provides a valuable process for making (R)-3-(2,3-dihydroxypropyl)-6-fluoro-5-(2-fluoro-4-iodophenylamino)-8-methylpyrido[2,3-d]pyrimidine-4,7(3H,8H)-dione characterized by the reaction of a compound of formula (8) with 2-fluoro-4-iodoaniline to give a compound of formula (9). Such a process avoids the use of costly and possible hazardous fluorinating regents in later steps which has significant advantages in large-scale manufacture.


Example 8.1(R)-3-(2,3-Dihydroxypropyl)-6-fluoro-5-(2-fluoro-4-iodophenylamino)-8-methylpyrido[2,3-d]pyrimidine-4,7(3H,8H)-dione
Combine (R)-3-((2,2-dimethyl-1,3-dioxolan-4-yl)methyl)-6-fluoro-5-(2-fluoro-4-iodophenylamino)-8-methylpyrido[2,3-d]pyrimidine-4,7(3H,8H)-dione (24.75 g, 45.58 mmol) and ethanol (250 mL). Add aqueous 9N sulfuric acid (50 mL) over 5 minutes. Heat to 75° C. After 2 hour, cool to ambient temperature and then cool in an ice bath to give a solid. Collect the solid by filtration, rinse with ethanol (3×30 mL), and dry to give the title compound. 

 
 1H NMR (400 MHz, DMSO-d6) δ10.24 (s, 1H), 8.52 (s, 1H), 7.69 (dd, 1H, J=10.4, 1.8 Hz), 7.52 (d, 1H, J=8.6 Hz), 6.98 (m, 1H), 5.14 (brs, 1H), 4.83 (brs, 1H), 4.32 (dd, 1H, J=12.9, 2.5 Hz), 3.76 (m, 1H), 3.67 (dd, 1H, J=13.1, 12.9 Hz), 3.58 (s, 3H), 3.46 (ddd, 1H, J=10.9, 5.3, 5.1 Hz), 3.38 (m, 1H); 
 

 13C NMR (100 MHz, DMSO-d6) δ161.3 (d, J=4.0 Hz), 155.6 (d, J=22.8 Hz), 154.6 (d, J=250 Hz), 152.0, 150.6, 134.3 (d, J=231 Hz), 133.8 (d, J=7.1 Hz), 133.1 (d, J=3.0 Hz), 127.8 (d, J=10.3 Hz), 125.3 (d, J=7.0 Hz), 123.9 (d, J=21.5 Hz), 95.0 (d, J=4.0 Hz), 87.1 (d, J=7.8 Hz), 68.0, 63.8, 50.1, 28.8; 

 








19F NMR (376 MHz, DMSO-d6) δ-124.4, −149.8; 
 

MS (M+H)+m/z calcd 505.0. found 505.0.

SEE

http://newdrugapprovals.org/2014/11/20/tak-733-clinical-studies-for-cancer-treatment/



http://newdrugapprovals.org/2014/11/20/tak-733-clinical-studies-for-cancer-treatment/



http://newdrugapprovals.org/2014/11/20/tak-733-clinical-studies-for-cancer-treatment/


http://newdrugapprovals.org/2014/11/20/tak-733-clinical-studies-for-cancer-treatment/

CIS TRANS ISOMERS AND NMR








 










Cis and trans coupling appear differently on 1H NMR spectrum

Here are a couple of terms to know:
  • Vicinal - Coupling between hydrogens on adjacent carbons. 
  • Geminal - Coupling between nonequivalent hydrogens on the same carbon atom. 

Coupling Constants Around a Double Bond
Type of couplingNameRange (Hz)Typical (Hz)
File:Organic_Chemistry/Hydrocarbons/Alkenes/Properties_of_Alkenes/Nuclear_Magnetic_Resonance_(NMR)_of_Alkenes/cis.bmpVicinal, cis6-1410
File:Organic_Chemistry/Hydrocarbons/Alkenes/Properties_of_Alkenes/Nuclear_Magnetic_Resonance_(NMR)_of_Alkenes/trans.bmpVicinal, trans11-1816
geminal.bmpGeminal0-32

             None.bmp
None4-106
          Allylic.bmpAllylic0.5-3.02

When alkynel hydrogen atoms are not symmetrically substituted on a double bonded carbon, the hydrogens of a cis and trans isomer will yield a different shift on the NMR spectrum. Because the coupling constant is smaller in a cis isomer than in a trans isomer, the NMR spectrums of the two isomers are different conveying the hydrogens in a cis isomer to be slightly more upfield to-- the right of the spectrum-- and trans hydrogens to be more downfield to the left.                                                  
isomers.bmp
Sometimes coupling will lead to very complicated patterns as a result of the J values that vary widely due to the relationship between the hydrogens involved. When this occurs, information can still be derived to determine the structure of a molecule by looking at the number of signals, the chemical shift of each one, integration, and splitting patterns similarly to identifying alkane NMR. 

Alkenyl carbons are deshielded in 13C NMR

For background information on 13C NMR, please refer to 13C Nuclear Magnetic Resonance from the previous chapter. Compared to alkane carbons with one bond, alkene carbons show a relatively low field shift on the 13C NMR spectrum and absorb about 100 ppm lower field. Also, in broad-band decoupled 13C NMR, sp2 carbons absorb as sharp single lines so with these two methods, it is easy to determine the presence of a double bond in 13C NMR spectrum.
Here are the common 13C Chemical Shift Ranges:
cnmr1.gif
Note that the carbon-carbon double bonds are found in the range between 100-170 ppm. Carbon atoms on alkenes that are attatched to another carbon group are found more downfield than carbon alkenes attatched to hydrogens.
Let's try a 1H NMR practice problem with C4H7Cl:
NMRex2.bmp
 Remember from previous sections that to solve an NMR spectrum with double bonds, we must know the Degrees of Unsaturation. From this, we get degrees of unsaturation= (9-7)/2=1 so there is one pi bond or ring in our molecule. Next we must look at the integration of the NMR spectrums.
  • ppm= 1.8 with 3H reveals a CH3attached to an unsaturated functional group
  • ppm= 4.0 with integration of 2H is a CH2 most likely attached to the Cl
  • ppm = 4.9 and 5.1 are singlets of 1H and must be our two alkene hydrogens
There are three ways to attach the discovery we made, but only one of them are the correct answer. Since the coupling of the two alkene hydrogens are small whereas vicinal hydrogens tend to be large, we conclude that the hydrogens are geminal and appear on the same carbon. This leaves the two other groups to be located on the other alkene carbon.


Stereo Chemical Information from coupling constant

Distinction between cis and trans isomers
Trans coupling is greater than for cis. From the value the isomers can be identified as in the following example.
stereochemical Information
  • For coupling the two hydrogens must have different chemical shift.
  • Trans coupling (range :11 to 19 Hz) is greater than cis coupling (range: 5 to 14 Hz).
  • 3JHH means coupling between two hydrogens separated by a distance of three bonds (vicinal coupling). If it is coupling between hydrogens at the same carbon then it is 2JHH (geminal coupling)
In some molecules the cis-trans, distinction is made even from the position of the absorption, as in cis and trans stilbenes. In trans case the hydrogens are deshielded by two aromatic rings while in the cis case it is by one ring.
Stereochemical Information

Variation of dihedral angle with coupling constant

Dihedral angle: Consider the following Newman and Sawhorse projections for ethane.
Dihedral angle, Newman and sawhorse projections for ethane
  • Looking from the front Hb is eclipsed by Ha the angle between the plane containing Ha and Hb is zero (they are in the same plane).
  • The second conformation has Hb at a different spatial position, they are not in the same plane. The plane containing Hb is 600 to the right of the plane containing Ha. This is the dihedral angle, in the first case the dihedral angle is zero.
  • In the third case though the two atoms are in the same plane Hb has undergone a rotation of 1800 and that is the dihedral angle.
  • The dihedral angle is used when two are separated by three bonds.
  • Martin Karplus was the first to study the variation of coupling constant 3JHH with dihedral angle.
  • The magnitude of the coupling constant between hydrogens of adjacent carbon atoms depend directly on the dihedral angle.
  • This magnitude is greatest when this is zero or 1800 and smallest when it is 900.
  • When it is zero side-side overlap of the two C-H bond orbitals will be maximum, when it is 1800 back lobes overlap is maximum leading to higher “J”. When it is 600 C-H bond orbitals overlap is at a minimum since they are perpendicular with each other leading to lower “J”.

Stereochemistry of cyclohexane derivatives

Stereochemistry of cyclohexane derivatives
The information from the above can be used to assign the configuration of the anomeric carbon in cyclic sugars. In the case of α- glucose at the anomeric carbon the equatorial proton is has a chemical shift of δ 5.2 which is down field by 0.5 for the corresponding axial proton in β-glucose.


 Coupling Constants : Cis-Trans Isomers of Olefins
The magnitude of the 3J(H,H) coupling constant in olefins follows the general rule Jtrans > Jcis and this is a convenient way to distinguish between cis and trans isomers:
 
 
3J is also influenced by the olefin's substituents, the distinction is meaningful only for one by direct comparison of the isomers or for olefins with very similar substitution pattern.


( Z ) - hex - 2 - en - 1 - yl acetate








(Z)-hex-3-en-1-yl acetate

 ( E ) - hex - 2 - en - 1 - yl  acetate







(2E)-Hex-2-en-1-yl acetate
(E)-2-Hexenyl acetate





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City in India
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Famotidine

Famotidine.svgFamotidine-from-xtal-polymorph-A-3D-balls.png
FAMOTIDINE
76824-35-6
3-(2-Guanidinothiazol-4-ylmethylthio)-N-sulfamoylpropanamidine
MK-208
YM-11170
YM-1170
Histamine H2 Receptor Antagonists
Gastroesophageal Reflux Disease,
Agents forGastric Antisecretory Drugs (GERD)
Astellas Pharma (Innovaator)Launched – 1985




read at
http://newdrugapprovals.org/2014/11/19/famotidine/

Aplaviroc hydrochloride


Aplaviroc.svg
Aplaviroc
4-(4-{[(3R)-1-butyl-3-[(R)-cyclohexylhydroxymethyl]-2,5-dioxo- 1,4,9-triazaspiro[5.5]undecan-9-yl]methyl}phenoxy)benzoic acid
for the treatment of HIV infection
461023-63-2 of hydrochloride
461443-59-4 (free base)
873140
AK-602
GW-873140
ONO-4128
ono…….innovator
Ono Pharmaceutical Co., Ltd.
Base
4-[4-[[(3R)-1-Butyl-3-[(R)-cyclohexylhydroxymethyl]-2,5-dioxo-1,4,9-triazaspiro[5.5]undec-9-yl]methyl]phenoxy]benzoic acid
(3R)-1-butyl-2,5-dioxo-3-[(1R)-1-hydroxy-1-cyclohexylmethyl]-9-[4-(4-carboxyphenyloxy)phenylmethyl]-1,4,9-triazaspiro[5.5]undecane
Molecular Formula: C33H43N3O6
Molecular Weight: 577.71
Percent Composition: C 68.61%, H 7.50%, N 7.27%, O 16.62%
References: CCR5 chemokine receptor antagonist; inhibits HIV entry by blocking interaction of viral coat protein gp120 with the receptor. Prepn: H. Habashita et al., WO02074770 (2002 to Ono); eidem, US 04082584 (2004).
Study of CCR5 binding and mechanism of action: C. Watson et al., Mol. Pharmacol. 67, 1268 (2005).
Antiretroviral activity in immunodeficient mice: H. Nakata et al., J. Virol. 79, 2087 (2005). Clinical pharmacokinetics: K. K. Adkison et al., Antimicrob. Agents Chemother. 49, 2802 (2005).
Derivative Type: Hydrochloride
CAS Registry Number: 461023-63-2
Manufacturers’ Codes: AK-602; GW-873140; ONO-4128
Molecular Formula: C33H43N3O6.HCl
Molecular Weight: 614.17
Percent Composition: C 64.53%, H 7.22%, N 6.84%, O 15.63%, Cl 5.77%
Therap-Cat: Antiviral.
aplaviroc.png
IDENTIFIERS
CAS NUMBER461023-63-2 Yes
ATC CODENone
PUBCHEMCID 3001322
CHEMSPIDER2272720 Yes
UNII98B425P30V Yes
KEGGD06557 Yes
CHEMBLCHEMBL1255794
CHEMICAL DATA
FORMULAC33H43N3O6 
MOL. MASS577.711 g/mol

Aplaviroc (INN, codenamed AK602 and GSK-873140) is a CCR5 entry inhibitor developed for the treatment of HIV infection.[1][2] It is developed by GlaxoSmithKline.
In October 2005, all studies of aplaviroc were discontinued due to liver toxicity concerns.[3][4] Some authors have claimed that evidence of poor efficacy may have contributed to termination of the drug’s development;[5] the ASCENT study, one of the discontinued trials, showed aplaviroc to be under-effective in many patients even at high concentrations.[6]
Aplaviroc hydrochloride, an orally-effective, long-acting chemokine CCR5 receptor antagonist, had been under development by Ono and GlaxoSmithKline for the treatment of HIV infection. In early 2006, the companies discontinued development of the antagonist based on reports of elevated liver function test values from clinical studies.
Originally developed at Ono, aplaviroc was licensed to GlaxoSmithKline in 2003 for development, manufacturing and marketing. GlaxoSmithKline also obtained rights to evaluate the agent in non-HIV conditions worldwide with the exception of Japan, South Korea and Taiwan.
A low-molecular-weight compound, aplaviroc prevents HIV viral infection by blocking the binding of the virus to the CCR5 receptor
……………….
WO 2002074770
0r


Example 9(54)
    (3R)-1-butyl-2,5-dioxo-3-((1R)-1-hydroxy-1-cyclohexylmethyl)-9-(4-(4-carboxyphenyloxy)phenylmethyl)-1,4,9-triazaspiro[5.5]undecane • hydrochloride
  • [0359]
    Figure 01740001
    TLC:Rf 0.43(chloroform:methanol = 5:1);
    NMR (CD3OD):δ 8.05 (d, J = 9.0 Hz, 2H), 7.61 (d, J = 9.0 Hz, 2H), 7.19 (d, J = 9.0 Hz, 2H), 7.08 (d, J = 9.0 Hz, 2H), 4.38 (s, 2H), 4.17 (d, J = 2.1 Hz, 1H), 4.02 (m, 1H), 3.78 (m, 1H), 3.60-3.40 (m, 3H), 3.30-3.10 (m, 2H), 2.56-1.86 (m, 6H), 1.82-1.60 (m, 5H), 1.52-1.16 (m, 6H), 1.06-0.82 (m, 2H), 0.97 (t, J = 7.2 Hz, 3H).

    read at
     http://newdrugapprovals.org/2014/11/19/aplaviroc-ak602-gsk-873140/